Front | Back |
If the power is increased by a factor of 2, what is the increase in power in dB?
|
3 dB (this was memorized)
|
If the power is increased by a factor of 3, what is the increase in power in dB?
|
2 dB (this was memorized)
|
If the power is increased by a factor of 6, what is the increase in power in dB?
|
4 dB (this was memorized)
2 x 2 = 4
|
If the power is increased by a factor of 9, what is the increase in power in dB?
|
8 dB (this was memorized)
2 x 2 x 2 = 8
|
If the initial power is 1 what is the increase in power in dB if the final is 10?
|
Pf / Pi 10W / 1W = 10
10 X log (10) = 10 x 1 = 10 dB
|
If the power decreased by a factor of 100, what is the decrease in power in dB?
|
Answer: -20 dB
Pf / Pi = 1 /100
10 x log 1/100 = -20dB or the power was decreased by 20 dB
|
The decible equation in amplitude form:
Conveting amplitude into power
|
DB = 20 x log Af / Ai
|
If initial amplitude is 0.1 but increased by a facotor of 100, what is the final amplitude, and what is the change in dB?
|
Answer = 40 dB
20 x log (100) = 20 x 2 = 40 dB
|
The acoustic pressure field is decreased by a factor of 10, in decibels, what is the change in power?
|
Pressure is a change in amplitude use amplitude form. 20 x log 1/10 = 20 x -1 = -20 dB
|
An decrease inpower by a factor of 2 is equal to _________dB.
|
Answer: -3 dB
|
An increase in power by a factor of 2 is equal to _________dB.
|
3 dB
|
An increase in power of a factor of 8 is equal to _________dB.
|
9 dB
|
An decrease in power of a factor of is equal to _________dB.
|
-3 dB
|
An increase in amplitude of a factor of 2 is equal to _________dB.
|
20 x log 100 = 20 x 2 = 40 dB
|
An decrease in amplitude of a factor of 2 is equal to _________dB.
|
20 x log -100 = 20 x -2 = -40 dB
|